Parfit's Argument that I am Not Both
(in reference to the division case)

Proof by reductio:

Assume I am both R and S.
That is, I = R, and I = S (where "=" means "is literally the same thing as")
So, R = S (by symmetry and transitivity of "=")
But, R is 
not the same thing 
as S.
Contradiction!
Hence, I am not both R and S. (by reductio)

This is proof of premise 2 of the overall argument.

Defense of "R is not 
the same thing as S": "They're going to live completely different lives. They're going to be as different as any two people are." (P 298a)


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Richard Lee, rlee@uark.edu, last modified: 22 November 2002